IBPS CWE Bank PO Clerical Recruitment Exams: May 2012

Syllabus Pattern IBPS CWE Bank PO Common Written Exam:

Objective paper

Time Allowed: 150 Minutes (or 2.5 Hours)

1. Reasoning (50 Qs, 50 Marks)

2. English Language (50 Qs, 25 Marks)

3. Quantitative Aptitude (50 Qs, 50 Marks)

4. General Awareness (with special reference to Banking Industry) (50 Qs, 50 Marks)

5. Computer Knowledge (50 Qs, 50 Marks)

Descriptive Paper on English Composition:

1. Essay, Précis, Letter Writing etc. (25 Marks)

Time Allowed: 60 Minutes (or 1 Hour)

Negative Marking:

One fourth or 0.25 times the marks assigned to that question will be deducted as penalty for incorrect answers.

CWE Score Card

IBPS will print the Score Cards for each of the qualifying candidates and will send the same by Registered/ Speed post to each candidate at the correspondence address specified in his/ her online application.

Score Cards issued by IBPS will be valid for one year from the date of issue of the Score Card. Candidates can appear in subsequent examination(s) to enhance their scores if they so desire.

Bank Clerk / Clerical & Assistants Solved Sample Paper Numerical Ability For IBPS CWE

1. 1/2 of 3842 + 15 % of ? = 2449

1) 3520

2) 3250

3) 3350

4) 3540

5) None of these

Ans: (1)
Solution:

1/2 of 3842 + 15 % of ? = 2449

1921 + 15/100 x ? = 2449

? = 528 x 100/15

= 3520

2. (833.25 – 384.45) ÷ 24 = ?

1) 1.87

2) 20.1

3) 2.01

4) 18.7

5) None of these

Ans: (4)
Solution:

(833.25 – 384.45) ÷ 24 = ?

448.80 / 24 = 18.7

3. 350% of ? ÷ 50 + 248= 591

1) 4900

2) 4890

3) 4850

4) 4950

5) None of these

Ans: (1)
Solution:

350% of ? ÷ 50 + 248= 591
350/100 X ?/50 = 343

? = 343 X 100/7

= 4900

4. 7960 + 2956 - 8050 + 4028 = ?

1) 6984

2) 6884

3) 6894

4) 6954

5) None of these

Ans: (3)

Solution:

7960 + 2956 - 8050 + 4028 = ?
14944 - 8050 = 6894

5. 25 × 3.25 + 50.4 ÷ 24 =?

1) 84.50

2) 83.35

3) 83.53

4) 82.45

5) None ofthese

Ans: (2)

Solution:

25 × 3.25 + 50.4 ÷ 24 =?
81.25 + 2.1 = 83.35

Direction (Q.6-10): What should come in place of the question mark (?) in the following questions?

6. 15     25     40     65   ?     170

1) 115

2) 90

3) 105

4) 120

5) 105

Ans: (5)

Solution
15 + 25 = 40, 25+ 40 =65 and 40 + 65 = 105

7. 120     320     ?     2070          5195        13007.5

1) 800

2) 920

3) 850

4) 900

5) None of these

Ans: (5)

8. 620     632     608     644     596   ?

1) 536

2) 556

3) 656

4) 646

5) None of these

Ans: (3)
Solution:

620 + 12 = 632, 620 – 12 = 608, 632 + 12 = 644,

608 – 12 = 596, so 644 + 12 = 656

9. 325      314       288      247     191 ?

1) 126

2) 116

3) 130

4) 120

5) None of these

Ans: (4)
Solution:

The next number in the series is decreased by 11, 26, 41, 56 and so on.

Here the next number decreased is 15 more. So next number will be 191 – ( 56 + 15 ) = 120

10. 45     46     70     141   ?   1061.5

1) 353

2) 353.5

3) 352.5

4) 352

5) None of these

Ans: (2)
Solution:

45 x 1 + 1 = 46,

70 x 2 + 1 = 141,

? x 3 + 1 = 1061.5

11. Sonika invested an amount of Rs 5800 for 2 years. At what rate of compound interest will she get an amount of Rs 594.50 at the end of two years?

1) 5 pcpa

2) 4 pcpa

3) 6 pcpa

4) 8 pcpa

5) None of these

Ans: (1)

Solution;

6394.50/5800 = (1+R/100) square

441/400 = (1+R/100) square

(21/20) square = (1+R/100) square

21/20 = (1+R/100)

R= 5

12. If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51 . What is the original fraction?

1) 11/17

2) 11/15

3) 15/17

4) 13/15

5) None of these

Ans: (3)

Solution:

2.5x/4.5y = 25/51

x/y = 15/17

13. In how many different ways can the letters of the word 'BANKING' be arranged?

1) 5040

2) 2540

3) 5080

4) 2520

5) None of these

Ans: (4)

Solution;

7!/2! = 7x6x5x4x3= 2520

14. Meenal purchased a car for Rs 2, 50, 000 and sold it for Rs 3, 48, 000. What is the per cent profit she made on the car?

1) 40

2) 39.2

3) 38.4

4) 38

5) None of these

Ans: (2)

Solution:

98000 x 100/250000 = 39.2%

15. There are some parrots and some tigers in a forest. If the total number of animal heads in the forest is 858 and the total number of animal legs is 1,846, what is the number of parrots in the forest?

1) 845

2) 833

3) 800

4) Cannot be determined

5) 793

Ans: (5)

Hint; Apply Alligation and Mixture

Directions (Q.16-20): Study the following table carefully and answer the questions given below it.

Cities	Shows (Number in hundreds)
Cities	Dance	Music	Drama	Stand-up Comedy	Mimicry
M	15	21	24	0.8	0.9
N	12.4	13	26	2	0.5
O	5.7	8	12	0.3	0.2
P	11.3	6	18	1	1.5
Q	17	12.4	11	3	0.4
R	14	10.5	9.8	0.7	0.1

16. The mimicry shows held in city M are what per cent of the drama shows held in city O?

1) 7

2) 8.5

3) 6.5

4) 8

5) 7.5%

Ans: (5)

Solution:

90x100/1200 = 7.5%

17. What is the average number of entertainment shows held in city P?

1) 756

2) 678

3) 786

4) 698

5) None of these

Ans: (1)

Solution:

3780/5 = 756

18. If the number of music shows in city N and Q is increased by 5%, what will be the total number of music shows in both the cities together?

1) 2,602

2) 2,667

3) 2,540

4) 2,605

5) None of these

Ans: (2)

Solution:

2540 x 105/100 = 2667

19. What is the ratio of the number of dance shows held in city N to the number of drama shows held in city R?

1) 49 : 62

2) 49 : 51

3) 62 : 45

4) 62 : 49

5) None of these

Ans: (4)

Solution:

1240:980 = 62:49

20. What is the total number of stand-up comedy shows held in all the cities together?

1) 820

2) 740

3) 780

4) 810

5) None of these

Ans: (3)

Solution:

80+200+30+100+300+70=780

21. By how much is 3/4 of 968 less than 7/8 of 1008?

1) 154

2) 146

3) 165

4) 158

5) 156

Ans: (5)
Solution:

3/4 of 968 =726

7/8 of 1008= 882

882 – 726 = 156

22. There are two numbers such that the sum of twice the first number and twice the second number is 100 and the sum of thrice the first number and twice the second number is 120. Which is the larger number?

1) 30

2) 12

3) 14

4) 35

5) None of these

Ans: (1)

3x + 2y = 120

2x + 2y = 100

So x = 20 and y = 30

23. When-all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed?

1) 25

2) 42

3) 36

4) 32

5) None of these

Ans: (3)
Solution:

54 x 30/45 = 36

24. The ratio of the present ages of Anju and Sandhya is 13: 17. Four years ago the ratio of their ages was 11: 15. What will be the ratio of their ages six years hence?

1) 3 : 4

2) 7 : 8

3) 5 : 4

4) 6 : 5

5) 4 : 5

Ans: (5)

13x - 4/ 17x – 4 = 11/15

X = 2

Anju’s Present age = 26

Sandhya’s Present age = 34

six years hence = 32 & 40 i.e. 4 : 5

25. The average age of 80 boys in a class is 15. The average age of a group of 15 boys in the class is 16 and the average age of another 25 boys in the class is 14. What is the average age of the remaining boys in the class?

1) 15.25

2) 14

3) 14.75

4) Cannot be determined

5) None of these

Ans: (1)
Total age (sum) of all 80 students = 80 x 15 = 1200

Total age (sum) of 15 students = 15 x 16 = 240

Total age (sum) of 25 students = 25 x 14 = 350

Total age (sum) of remaining 40 students = 1200 – ( 240 + 350 ) = 610

Average of remaining 40 students = 610/40 = 15.25

IBPS CWE Bank PO Clerical Recruitment Exams

Punjab Recruitments

Thursday, May 31, 2012

IBPS CWE RRB Regional Rural Banks Recruitment 2012 Common Written Exam For Officers & Assistants

Tuesday, May 29, 2012

Syllabus Pattern IBPS CWE Bank PO Common Written Exam:

Objective paper

Descriptive Paper on English Composition:

Negative Marking:

CWE Score Card

IBPS CWE Bank Clerk Clerical Assistants Solved Sample Paper Numerical Ability

Bank Clerk / Clerical & Assistants Solved Sample Paper Numerical Ability For IBPS CWE

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Monday, May 28, 2012

IBPS RRB Regional Rural Banks CWE Recruitment 2012 Officer Assistants

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